r8169: use RxFIFO overflow workaround for 8168c chipset.
authorIvan Vecera <ivecera@redhat.com>
Thu, 27 Jan 2011 11:24:11 +0000 (12:24 +0100)
committerGreg Kroah-Hartman <gregkh@suse.de>
Mon, 14 Mar 2011 21:17:38 +0000 (14:17 -0700)
commit b5ba6d12bdac21bc0620a5089e0f24e362645efd upstream.

I found that one of the 8168c chipsets (concretely XID 1c4000c0) starts
generating RxFIFO overflow errors. The result is an infinite loop in
interrupt handler as the RxFIFOOver is handled only for ...MAC_VER_11.
With the workaround everything goes fine.

Signed-off-by: Ivan Vecera <ivecera@redhat.com>
Acked-by: Francois Romieu <romieu@fr.zoreil.com>
Cc: Hayes <hayeswang@realtek.com>
Signed-off-by: Greg Kroah-Hartman <gregkh@suse.de>
drivers/net/r8169.c

index 3f70a2f964b55c05b3417842ba33e2a3897ccb73..57789e1933a4b226133a1dae3cc70683432c504a 100644 (file)
@@ -3725,7 +3725,8 @@ static void rtl_hw_start_8168(struct net_device *dev)
        RTL_W16(IntrMitigate, 0x5151);
 
        /* Work around for RxFIFO overflow. */
-       if (tp->mac_version == RTL_GIGA_MAC_VER_11) {
+       if (tp->mac_version == RTL_GIGA_MAC_VER_11 ||
+           tp->mac_version == RTL_GIGA_MAC_VER_22) {
                tp->intr_event |= RxFIFOOver | PCSTimeout;
                tp->intr_event &= ~RxOverflow;
        }
@@ -4604,7 +4605,8 @@ static irqreturn_t rtl8169_interrupt(int irq, void *dev_instance)
 
                /* Work around for rx fifo overflow */
                if (unlikely(status & RxFIFOOver) &&
-               (tp->mac_version == RTL_GIGA_MAC_VER_11)) {
+                   (tp->mac_version == RTL_GIGA_MAC_VER_11 ||
+                    tp->mac_version == RTL_GIGA_MAC_VER_22)) {
                        netif_stop_queue(dev);
                        rtl8169_tx_timeout(dev);
                        break;